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[Scheme-reports] r7rs-draft-6: circular datum example

In section 2.4, I believe that the . (dot) in the example closing the 

    #1=(begin (display #\x) . #1#)

is misleading, because even with a non-circular reference this code would
be an error, such as:

   (begin #1=(begin (display #\y)) (begin (display #\x) . #1#))

I suggest to simply remove the . (dot) so that the expression would be
well-formed in the absence of circularity.
Daniel Villeneuve
AD OPT, a Kronos Division

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